For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: ( T in kelvins)
And the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
A body in a room at 300 K is heated to 3,000 K. The amount of energy radiated each second by the body increases by a factor of

Question

For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature:  ( T in kelvins)
And the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to:  (  in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
A body in a room at 300 K is heated to 3,000 K. The amount of energy radiated each second by the body increases by a factor of

Quizplus · Accepted Answer

According to Stefan-Boltzmann law, the power emitted by the body is proportional to the fourth power of its absolute temperature (T). 
So, if the temperature increases from 300 K to 3000 K, then the amount of energy radiated each second by the body will increase by a factor of (3000/300)^4 = 10^4, which means D is the correct choice.

For a Body Emitting Blackbody Radiation, the Total Power Emitted