For a Body Emitting Blackbody Radiation, the Total Power Emitted

For a body emitting blackbody radiation, the total power emitted is proportional to the 4th power of the body's absolute temperature: ( T in kelvins)
And the wavelength of the emitted EM radiation that has the highest intensity is inversely proportional to the body's absolute temperature according to: ( in meters, T in kelvins)
Assume an object is emitting blackbody radiation.
A body in a room at 300 K is heated to 3,000 K. The wavelength of the most intense EM radiation emitted by the body at 3,000 K is the wavelength of the most intense EM radiation at 300 K.

A) 0.0001 times
B) 0.1 times
C) the same as
D) 10 times
E) 10,000 times