Mary Jo has $4.65 worth of nickels, dimes, and quarters. The number of nickels is 2 more than the number of dimes. The number of quarters is 7 more than the number of dimes. How many of each coin does she have? ( Hint : Let x = the number of dimes.)
A)11 nickels, 9 dimes and 16 quarters
B)7 nickels, 5 dimes and 12 quarters
C)6 nickels, 4 dimes and 11 quarters
D)14 nickels, 12 dimes and 19 quarters
E)9 nickels, 7 dimes and 14 quarters

Question

Quizplus · Accepted Answer

Let x be the number of dimes. Then, nickels = x + 2 and quarters = x + 7. The total value is 0.05(x + 2) + 0.10x + 0.25(x + 7) = 4.65. Solving this equation gives x = 7 dimes, so there are 9 nickels and 14 quarters.

Mary Jo Has $4