What is the oxidation number of the silicon in SiBr₄?

Name: What is the oxidation number of the silicon in SiBr 4 ?
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Question

Quizplus · Accepted Answer

The oxidation number of bromine is -1 and sulfur is -2. Therefore, the total oxidation number for the compound is:
Si + 2Br + S + 2B + S + 1B = 0
x + 2(-1) + (-2) + 2(3) + (-2) + 4 = 0
Solving for x, we get:
x = +4
Therefore, the oxidation number of silicon is +4. The correct choice is D.

What Is the Oxidation Number of the Silicon in SiBr4

What Is the Oxidation Number of the Silicon in SiBr₄