What is the empirical formula of a substance containing 92.3% C and 7.7% H?

Question

Quizplus · Accepted Answer

Assume we have 100 grams of the substance, then we have 92.3 grams of C and 7.7 grams of H. 
To find the empirical formula, we need to convert the grams of each element to moles. 
- Moles of C = 92.3 g / 12.01 g/mol = 7.694 mol 
- Moles of H = 7.7 g / 1.008 g/mol = 7.637 mol

Then, we divide each mole value by the smallest mole value to get the simplest whole number ratio of atoms. 
- Ratio of C = 7.694 mol / 7.637 mol = 1.007 
- Ratio of H = 7.637 mol / 7.637 mol = 1

Round these ratios to the nearest whole number to get the subscripts in the empirical formula. 
- Empirical formula = CH

What Is the Empirical Formula of a Substance Containing 92