In the reaction of 5.44 g of H₂ with excess N₂, a chemist isolates 7.56 g of NH₃. What is the percent yield in the reaction?

Question

Quizplus · Accepted Answer

To find the percent yield, first calculate the theoretical yield of NH₃. The balanced equation is N₂ + 3H₂ → 2NH₃. Moles of H₂ = 5.44 g / 2.02 g/mol = 2.693 moles. Theoretical moles of NH₃ = 2.693 moles H₂ * (2 moles NH₃ / 3 moles H₂) = 1.795 moles NH₃. Theoretical mass of NH₃ = 1.795 moles * 17.03 g/mol = 30.56 g. Percent yield = (7.56 g / 30.56 g) * 100% = 24.7%.

In the Reaction of 5