Exhibit 3-2 Aluminum sulfide, Al2S3 (molar mass = 150.16 g/mol) , reacts with water to form the aluminum hydroxide, Al(OH) 3 (molar mass = 78.00 g/mol) , and hydrogen sulfide, H2S, as shown below:
__ Al2S3 + __ H2O→__ Al(OH) 3 + __ H2S (unbalanced reaction)
Refer to Exhibit 3-2. How many molecules of H2S are prepared from 10.5 g of Al2S3?
A) 8.72×10 - 22 H2S molecules
B) 1.40×1022 H2S molecules
C) 4.21×1022 molecule of H2S
D) 1.26×1023 H2S molecules
E) 1.81×1024 H2S molecules
Correct Answer:
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