How many grams of NaCl are required to prepare 500. mL of an aqueous 0.500 M NaCl solution?
MM(NaCl) = 58.44 g/mol

Question

Quizplus · Accepted Answer

We can use the formula:
Molarity (M) = moles of solute (n) / volume of solution in liters (V)

Rearranging the formula, we get:
moles of solute (n) = Molarity (M) x volume of solution in liters (V)

Substituting the given values, we get:
n = 0.500 mol/L x 0.500 L = 0.25 mol

Now, we can use the molar mass of NaCl to convert the moles of NaCl to grams:
mass = moles x molar mass
mass = 0.25 mol x 58.44 g/mol = 14.61 g

Therefore, the answer is B (14.6 g NaCl).

How Many Grams of NaCl Are Required to Prepare 500