What is the molarity of a NaOH solution if the base in 50.0 mL of the solution is neutralized by 22.4 mL of 0.100 molar H₂SO₄?

Question

Quizplus · Accepted Answer

To solve this problem, we can use the following equation:

M₁V₁ = M₂V₂

where M₁ is the molarity of the acid (0.100 M, given), V₁ is the volume of the acid (22.4 mL, given), M₂ is the molarity of the base (what we're trying to find), and V₂ is the volume of the base (50.0 mL, given).

Plugging in the values we get:

(0.100 M)(22.4 mL) = M₂(50.0 mL)

M₂ = (0.100 M)(22.4 mL) / 50.0 mL

M₂ = 0.0448 M

However, this is the molarity of the acid. To find the molarity of the base, we need to take the negative reciprocal:

M_base = 1 / M_acid

M_base = 1 / 0.0448 M

M_base = 0.0896 M

Therefore, the answer is choice C: 0.0896 molar.

What Is the Molarity of a NaOH Solution If the Base