A sample of SF₆ gas occupies a volume of 5.01 L at 198 ° C. Assuming the pressure is constant, what temperature in ° C is needed to reduce the volume to 2.24 L?

Question

Quizplus · Accepted Answer

Using Charles's Law (V1/T1 = V2/T2), where temperatures are in Kelvin. Convert 198°C to Kelvin (198 + 273 = 471K) and solve for T2 after volume change (5.01L to 2.24L). T2 = (2.24L * 471K) / 5.01L ≈ 210.6K. Convert back to °C (210.6K - 273) ≈ -62.4°C, rounding gives -62.6°C.

A Sample of SF6 Gas Occupies a Volume of 5

A Sample of SF₆ Gas Occupies a Volume of 5