A fixed quantity of gas at 23.0 ° C exhibits a pressure of 748 torr and occupies a volume of 10.3 L. What volume will this gas occupy at 165 ° C and constant pressure?

Question

Quizplus · Accepted Answer

To solve this problem, we use the ideal gas law in the form of Charles's Law, which states that for a given mass of gas at constant pressure, the volume of the gas is directly proportional to its temperature in Kelvin. The formula to use is $V_1/T_1 = V_2/T_2$, where $V_1$ and $V_2$ are the initial and final volumes, and $T_1$ and $T_2$ are the initial and final temperatures in Kelvin, respectively.First, convert the temperatures from Celsius to Kelvin:- Initial temperature: $23.0 °C = 23.0 + 273.15 = 296.15 K$- Final temperature: $165 °C = 165 + 273.15 = 438.15 K$Given that $V_1 = 10.3 L$ and $T_1 = 296.15 K$, and $T_2 = 438.15 K$, we can solve for $V_2$ as follows:$$V_2 = V_1 \times \frac{T_2}{T_1} = 10.3 L \times \frac{438.15 K}{296.15 K} = 15.2 L$$Therefore, the volume the gas will occupy at 165 °C and constant pressure is 15.2 L.

A Fixed Quantity of Gas at 23