What is the pressure inside a 3.2 L jar that contains 2.6 g of N₂ gas at a temperature of 27 ° C?

Question

Quizplus · Accepted Answer

To find the pressure, use the ideal gas law: PV = nRT. First, convert 2.6 g of N2 to moles (2.6 g / 28.02 g/mol = 0.0928 mol). Convert 27 °C to Kelvin (27 + 273.15 = 300.15 K). Use R = 0.0821 L·atm/mol·K. Solve for P: P = (nRT) / V = (0.0928 mol * 0.0821 L·atm/mol·K * 300.15 K) / 3.2 L = 0.71 atm.

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