What is the pressure of a container if 0.221 mol of a gas in a 1.22 L container is at a temperature of 27 ° C?

Question

Quizplus · Accepted Answer

Use the ideal gas law equation:

PV = nRT

where 
P = pressure in atm 
V = volume in L 
n = number of moles 
R = gas constant (0.0821 L∙atm/K∙mol) 
T = temperature in Kelvin

First, convert the given temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15 
T(K) = 27 °C + 273.15 
T(K) = 300.15 K

Then, plug in the given values:

P(1.22 L) = (0.221 mol)(0.0821 L∙atm/K∙mol)(300.15 K)

Solve for P:

P = (0.221 mol)(0.0821 L∙atm/K∙mol)(300.15 K) / (1.22 L)

P = 4.46 atm

Therefore, the answer is C.

What Is the Pressure of a Container If 0