It takes 200 seconds for a sample of gas Y to effuse through a porous plug and 100 seconds for the same amount of CH₄ to effuse under the same conditions. What is the molar mass of gas Y?

Question

Quizplus · Accepted Answer

According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Using this formula, we can set up the following proportion: (rate of effusion of Y)/(rate of effusion of CH₄) = √(molar mass of CH₄) / √(molar mass of Y) Simplifying and solving for the molar mass of Y, we get: molar mass of Y = (molar mass of CH₄) x (rate of effusion of Y / rate of effusion of CH₄)^2 Plugging in the given values, we get: molar mass of Y = 342 g/mol x (1/2)^2 = 64 g/mol

It Takes 200 Seconds for a Sample of Gas Y