The ground state electron configuration of P⁺ is:

Question

Quizplus · Accepted Answer

PS1U1P1+S1S1P0 has a total of 16 electrons. The noble gas configuration of the element before phosphorus (which has 15 electrons) is Neon with the electron configuration [He]2s22p6. Therefore, we can start with the configuration [Ne] for PS1U1P1+S1S1P0. 
The remaining electron is in the 3s orbital, so we add 3s1. 
Next, we have to fill the 2p and 3p orbitals. We add 2 electrons in the 2p orbital as S1U1P1 has 2 electrons, and the remaining 5 electrons in the 3p orbital, giving 3p5. 
Finally, we add the remaining electron in the 3d orbital. 
Therefore, the ground state electron configuration of PS1U1P1+S1S1P0 is [Ne]3sS1U1P12S1S1P03pS1U1P12S1S1P0.

The Ground State Electron Configuration of P+ Is

The Ground State Electron Configuration of P⁺ Is