How many grams of H₂SO₄ are present in 75.0 mL of 12.0 M H₂SO₄?
MM (H₂SO₄) = 98.09 g/mol

Question

How many grams of H₂SO₄ are present in 75.0 mL of 12.0 M H₂SO₄? MM (H₂SO₄) = 98.09 g/mol

Quizplus · Accepted Answer

First, we need to use the given concentration of the solution (12.0 M) to find the moles of H₂SO₄ present in 75.0 mL of the solution: molarity = moles / volume 12.0 M = moles / 0.075 L moles = 0.9 Next, we can use the molar mass of H₂SO₄ to convert moles to grams: grams = moles x molar mass grams = 0.9 x 98.09 grams = 88.3 Therefore, there are 88.3 grams of H₂SO₄ present in 75.0 mL of 12.0 M solution, making choice D the correct answer.

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