How many grams of LiNO₃ must be added to 235 grams of water to prepare a 40.0% (m/m) solution of LiNO₃?

Question

Quizplus · Accepted Answer

First, we need to calculate the mass of LiNO₃ needed to prepare the solution. If the solution is 40.0% (m/m), then 100 grams of solution will contain 40 grams of LiNO₃ and 60 grams of water. Therefore, we can set up the following proportion: 40 g LiNO₃ / 100 g solution = x g LiNO₃ / 235 g water + x g LiNO₃ Solving for x, we get: x = (40 g LiNO₃ / 100 g solution) * 235 g water / (1 - 40 g LiNO₃ / 100 g solution) x = 157 g LiNO₃ Therefore, we need 157 g of LiNO₃ to prepare the solution.

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