How many grams of sulfur, S₈ must be dissolved in 100. grams of naphthalene, C₁₀H₈, to make a 0.180 m solution?
Molar Mass(S₈) = 256.48 g/mol

Question

How many grams of sulfur, S₈ must be dissolved in 100. grams of naphthalene, C₁₀H₈, to make a 0.180 m solution? Molar Mass(S₈) = 256.48 g/mol

Quizplus · Accepted Answer

First, we need to calculate the moles of naphthalene in 100. grams: moles of naphthalene = mass / molar mass = 100. g / 128.17 g/mol (molar mass of naphthalene) = 0.7803 mol Next, we can use the molarity formula to calculate the moles of sulfur needed: moles of sulfur = molarity x liters of solution We are making 0.180 m solution, so we need to calculate the volume of solution in liters: mass of naphthalene = density x volume volume = mass of naphthalene / density = 100. g / 1.14 g/mL (density of naphthalene) = 87.72 mL Now we can convert mL to L: 87.72 mL x (1 L / 1000 mL) = 0.08772 L So our final equation is: moles of sulfur = 0.180 mol/L x 0.08772 L = 0.0158 mol S₈ Finally, we can convert moles to grams using the molar mass of sulfur: mass of sulfur = moles x molar mass = 0.0158 mol x 256.48 g/mol = 4.062 g Therefore, the best choice is B), 4.62 g S₈.

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