What is the vapor pressure of a solution of 30.0 g glycerol (C₃H₈O₃) in 504.5 grams of water at 25 ° C. The vapor pressure of pure water at 25 ° C is 23.76 torr and Molar Mass(C₃H₈O₃) = 92.09 g/mol.

Question

Quizplus · Accepted Answer

The vapor pressure of the solution can be calculated using Raoult's Law, which states that the vapor pressure of a solution is directly proportional to the mole fraction of the solvent. First, calculate the moles of glycerol and water. For glycerol: $ \frac{30.0 \, \text{g}}{92.09 \, \text{g/mol}} = 0.326 \, \text{moles} $. For water: $ \frac{504.5 \, \text{g}}{18.015 \, \text{g/mol}} = 28.0 \, \text{moles} $. The mole fraction of water is $ \frac{28.0}{28.0 + 0.326} = 0.9885 $. The vapor pressure of the solution is $ 0.9885 \times 23.76 \, \text{torr} = 23.49 \, \text{torr} $.

What Is the Vapor Pressure of a Solution of 30