At 334 K the vapor pressure of benzene (C₆H₆) is 0.526 atm and that of toluene (C₇H₈) is 0.188 atm. In a solution containing 0.500 mole of benzene and 0.500 mole of toluene, what is the vapor pressure of toluene above the solution at 334K?

Question

Quizplus · Accepted Answer

The vapor pressure of toluene in the solution can be calculated using Raoult's law, which states that the partial pressure of a component in a mixture is equal to the mole fraction of the component in the liquid phase multiplied by its pure component vapor pressure. For toluene, this is (0.500 mole toluene / (0.500 mole benzene + 0.500 mole toluene)) * 0.188 atm = 0.094 atm.

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