Consider the following unbalanced reaction :
NO (g) + O2 (g) →N2O3 (g) After balancing this reaction, how is the rate expressions for each substance in this equation related?
A) Rate = D [NO]/ D t = D [O2]/ D t = D [N2O3]/ D t
B) Rate = -D [NO]/ D t = -D [O2]/3 D t = D [N2O3]/2 D t
C) Rate = - 2 D [NO]/ D t = -D [O2]/3 D t = D [N2O3]/2 D t
D) Rate = 4 D [NO]/ D t = D [O2]/ D t = - 2 D [N2O3]/ D t
E) Rate = -D [NO]/4 D t = -D [O2]/ D t = D [N2O3]/2 D t
Correct Answer:
Verified
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