Consider the following unbalanced reaction :
NO (g) + O₂ (g) →N₂O₃ (g) After balancing this reaction, how fast is [O₂] decreasing when [NO] is decreasing at a rate of 1.60×10^{- 4} mol/L × sec?

Question

Quizplus · Accepted Answer

The balanced equation is: 2NO (g) + O₂ (g)→2N₂O₃ (g)So, the rate of decrease of [O₂] is:-d[O₂]/dt = (1/2)d[NO]/dt = (1/2)(1.60×10^{- 4} mol/L × sec) = 8.0×10^{- 5} mol/L × sec

Consider the Following Unbalanced Reaction