What is the solubility of AgCl (s) ( K _sp = 1.7×10^{- 10}) in a 0.30 M NaCl solution?

Question

Quizplus · Accepted Answer

The solubility of AgCl in pure water is given by the Ksp value: 
Ksp = [Ag+][Cl-] = 1.7×10^-10
In a solution containing NaCl, the Na+ and Cl- ions will both be present and can affect the solubility of AgCl. To calculate the new solubility, we need to consider the common ion effect. The addition of NaCl will increase the concentration of Cl- ions in the solution, which will shift the equilibrium towards the solid AgCl. 
Using the common ion effect equation, we can find the new equilibrium concentration of Cl- ions:
[Cl-] = [NaCl] = 0.30 M
Now we can calculate the new solubility of AgCl:
Ksp = [Ag+][Cl-] = (x)(0.30)
1.7×10^-10 = x(0.30)
x = 5.7×10^-11 M
Therefore, the solubility of AgCl in a 0.30 M NaCl solution is 5.7×10^-11 M, which corresponds to answer choice D.

What Is the Solubility of AgCl (S) ( K sp

What Is the Solubility of AgCl (S) ( K _sp