At 37 ° C the autoionization constant of water is K _w = 2.4×10^{- 14}. What is the pH of pure water at 37 ° C?

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Quizplus · Accepted Answer

The pH of pure water is calculated using the formula pH = -log[H+], where [H+] is the concentration of hydrogen ions. At 37 °C, the autoionization constant of water (Kw) is 2.4×10^-14. Since water autoionizes into equal amounts of H+ and OH- ions, [H+] = [OH-] = sqrt(Kw) = sqrt(2.4×10^-14). Calculating this gives [H+] = 1.55×10^-7 M. Taking the negative logarithm of this concentration gives a pH of approximately 6.81.

At 37 ° C the Autoionization Constant of Water Is