Calculate the pOH of a solution made by dissolving 2.0 grams of NaOH (molar mass = 40.0 g/mol) in water and diluting tO₅ 00 mL.

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Quizplus · Accepted Answer

The molarity of NaOH is calculated by dividing the mass of NaOH by its molar mass and then by the volume of the solution in liters. For 2.0 grams of NaOH in 1.0 L (1000 mL) of solution, the molarity is $ \frac{2.0 \, \text{g}}{40.0 \, \text{g/mol}} \times \frac{1}{1.0 \, \text{L}} = 0.05 \, \text{M} $. Since NaOH is a strong base, it completely dissociates in water, so the concentration of OH- ions is also 0.05 M. The pOH is calculated using the formula $ \text{pOH} = -\log[OH^-] $, which gives $ \text{pOH} = -\log(0.05) = 1.00 $.

Calculate the POH of a Solution Made by Dissolving 2