50 mL of 0.50 M NaOH is added to enough water to make 1.0 liter of solution. Calculate the pH.

Question

Quizplus · Accepted Answer

The concentration of NaOH after dilution is calculated using the formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the initial concentration and volume, and $C_2$ and $V_2$ are the final concentration and volume, respectively. Substituting the given values, $0.50 \, \text{M} \times 0.050 \, \text{L} = C_2 \times 1.0 \, \text{L}$, we find $C_2 = 0.025 \, \text{M}$. Since NaOH is a strong base, it fully dissociates in water, and the concentration of OH- ions is also $0.025 \, \text{M}$. The pOH is calculated using the formula $pOH = -\log[OH^-]$, which gives $pOH = -\log(0.025) \approx 1.6$. The pH can then be found using the relation $pH + pOH = 14$, which gives $pH = 14 - 1.6 = 12.4$.

50 ML of 0