Exhibit 15-4 Consider dissolving NaF in water as shown in the equation below to answer the following question(s):
NaF (s) + H₂ O ( ) HF (aq) + NaOH (aq)
-Refer to Exhibit 15-4. What is the base ionization constant , K b , for this reaction?
K a (HF) = 6.8 10 - 4

Question

Exhibit 15-4 Consider dissolving NaF in water as shown in the equation below to answer the following question(s):
NaF (s) + H₂ O (  )  HF (aq) + NaOH (aq)
-Refer to Exhibit 15-4. What is the base ionization constant , K b , for this reaction?
K a (HF) = 6.8 10 - 4

Quizplus · Accepted Answer

The base ionization constant, $K_b$, can be found using the relationship $K_w = K_a \times K_b$, where $K_w$ is the ionization constant of water at 25°C, equal to $1.0 \times 10^{-14}$. Given $K_a = 6.8 \times 10^{-4}$, solving for $K_b$ gives $K_b = \frac{1.0 \times 10^{-14}}{6.8 \times 10^{-4}} = 1.47 \times 10^{-11}$.

Exhibit 15-4 Consider Dissolving NaF in Water as Shown in the Equation