Exhibit 15-6 Consider an aqueous 0.25 M solution of NaCN to answer the following question(s) .
-Refer to Exhibit 15-6. What is the base ionization constant, K _b, for CN^-?
K _a(HCN) = 4.9×10^{- 10}

Question

Exhibit 15-6 Consider an aqueous 0.25 M solution of NaCN to answer the following question(s). -Refer to Exhibit 15-6. What is the base ionization constant, K _b, for CN^-? K _a(HCN) = 4.9×10^{- 10}

Quizplus · Accepted Answer

The base ionization constant, Kb, for CN- can be calculated using the relation Kw = Ka * Kb, where Kw is the ion product of water (1.0×10^-14 at 25°C). Given Ka(HCN) = 4.9×10^-10, Kb = Kw / Ka = 1.0×10^-14 / 4.9×10^-10 = 2.0×10^-5.

Exhibit 15-6 Consider an Aqueous 0