What volume of 0.200 M H₂ SO₄is required to neutralize 50.0 mL of 0.100 M NaOH?
Assume the chemical equation is:
H₂ SO₄(aq) + 2 NaOH (aq) Na₂ SO₄(aq) + 2 H₂ O ( )

Question

What volume of 0.200 M H₂ SO₄is required to neutralize 50.0 mL of 0.100 M NaOH? Assume the chemical equation is: H₂ SO₄(aq) + 2 NaOH (aq) Na₂ SO₄(aq) + 2 H₂ O ( )

Quizplus · Accepted Answer

From the balanced chemical equation, we can see that 1 mole of H₂ SO₄ reacts with 2 moles of NaOH. Therefore, the moles of NaOH in 50.0 mL of 0.100 M solution can be calculated as:
moles of NaOH = (0.100 mol/L) x (50.0 mL / 1000 mL/L) = 0.005 mol
Since 1 mole of H₂ SO₄ reacts with 2 moles of NaOH, we need half the number of moles of H₂ SO₄, i.e. 0.0025 mol, to neutralize the given amount of NaOH. Now, we can use the molarity of H₂ SO₄ to calculate the required volume:
0.200 mol/L = 0.0025 mol / x L
x = 0.0125 L = 12.5 mL (rounded to 3 significant figures) 
Therefore, the required volume of 0.200 M H₂ SO₄ is 12.5 mL.

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