Given:
Cu (s) + 2 Ag⁺→2 Ag (s) + Cu²⁺ E ° = +0.46 V Cu²⁺ + H₂ (g) →Cu (s) + 2 H⁺ E ° = +0.34 V Find the standard potential for the cell reaction for:
2 Ag⁺ + H₂ (g) →2 Ag + 2 H⁺

Question

Quizplus · Accepted Answer

To find the standard potential for the given cell reaction, we need to add the two half-reactions together: Cu (s) + 2 Ag⁺ → 2 Ag (s) + Cu²⁺ (E° = +0.46 V) Cu²⁺ + H₂ (g) → Cu (s) + 2 H⁺ (E° = +0.34 V) If we reverse the second reaction and multiply it by 2, we can add the two reactions together to get the overall cell reaction: 2 Ag⁺ + H₂ (g) → 2 Ag (s) + 2 H⁺ Cu (s) + 2 Ag⁺ → 2 Ag (s) + Cu²⁺ _______________________________________________________________ Cu (s) + 2 Ag⁺ + H₂(g) → Cu²⁺ + 2 H⁺ Using the standard potentials of the individual reactions, we can calculate the standard potential for the cell reaction: E°cell = E°cathode - E°anode E°cell = (+0.34 V) - (+0.46 V) E°cell = -0.12 V Therefore, the best choice is D) -0.12 V.

Given: Cu (S) + 2 Ag+→2 Ag (S) + Cu2+ E

Given: Cu (S) + 2 Ag⁺→2 Ag (S) + Cu²⁺ E