Given:
F2 (g) + 2 e - ?2 F - E ° = +2.87 V Cr2O 72 - (aq) + 14 H+ (aq) + 6 e - ?2 Cr3+ (aq) + 7 H2O E ° = 1.33 V Li+ (aq) + 1 e - (aq) ?Li (s) E ° = - 3.05 V What is the proper arrangement for the order of increasing strength as an oxidizing agent ?
F2 (g) , Cr2O72 - (aq) and Li+ (aq)
A) (weakest oxidizing agent) F2 (g) - (aq) < Li+ (aq) (strongest)
B) (weakest oxidizing agent) Cr2O72 - (aq) < F2 (g) < Li+ (aq) (strongest)
C) (weakest oxidizing agent) Cr2O72 - (aq) < Li+ (aq) < F2 (g) (strongest)
D) (weakest oxidizing agent) Li+ (aq) - (aq) (strongest)
E) (weakest oxidizing agent) Li+ (aq) - (aq) < F2 (g) (strongest)
Correct Answer:
Verified
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