Given the standard reduction potentials:
Cd²⁺ (aq) + 2 e^-→Cd (s) E ° = - 0.40 V CdCO₃ (s) + 2 e^-→Cd (s) + CO₃^{2 -} (aq) E ° = - 0.74 V What is the solubility product of CdCO₃ (s) ?

Question

Given the standard reduction potentials: Cd²⁺ (aq) + 2 e^-→Cd (s) E ° = - 0.40 V CdCO₃ (s) + 2 e^-→Cd (s) + CO₃^{2 -} (aq) E ° = - 0.74 V What is the solubility product of CdCO₃ (s)?

Quizplus · Accepted Answer

The difference in standard reduction potentials is used to calculate the solubility product (Ksp). The Nernst equation relates the potential difference to the equilibrium constant. The potential difference is 0.34 V (0.40 V - (-0.74 V)). Using the equation ΔG° = -nFE° and ΔG° = -RTlnK, we find Ksp = 3×10^-12.

Given the Standard Reduction Potentials