How many geometric isomers are possible for the octahedral complex [Ru(H₂O)₂Cl₄]^-?

Question

Quizplus · Accepted Answer

In an octahedral complex, there are two types of geometric isomers: cis and trans. Since there are three bidentate ligands (H₂O, ₂Cl, ₄), there are three possible pairs of cis/trans isomers. Therefore, the total number of possible isomers is 2*2*2=8. However, one of the trans isomers is achiral and therefore cannot have a geometric isomer. Thus, the answer is 2.

How Many Geometric Isomers Are Possible for the Octahedral Complex