What is the correct Lewis structure for the molecule XeF₄?

Question

Quizplus · Accepted Answer

The correct Lewis structure for XeF₄ has 24 valence electrons. Since Xe is the central atom, it will have 8 valence electrons; F and S will have 6 valence electrons each, while B will have only 3 valence electrons. Therefore, we have: - Xe-F: 2 electrons (1 bond) - Xe-S: 2 electrons (1 bond) - Xe-B: 4 electrons (2 bonds) - B-S: 4 electrons (2 bonds) - B-S: 4 electrons (2 bonds) - B-F: 2 electrons (1 bond) - B-F: 2 electrons (1 bond) Adding all electrons, we get 2+2+4+4+4+2+2 = 20 electrons used. The remaining 4 electrons will be placed on the Xe atom, as lone pairs. The resulting structure is choice B.

What Is the Correct Lewis Structure for the Molecule XeF4

What Is the Correct Lewis Structure for the Molecule XeF₄