If the absolute magnitude, M , of a supernova is − 19 and a galaxy is found that contains a supernova with an apparent magnitude, m , of 16. What is the distance to the galaxy? Hint: d _pc = 10^{( m - M + 5)/5} A) 100 AU B) 100 pc C) 100 ly D) 100 kpc E) 100 Mpc

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Quizplus · Accepted Answer

Using the distance modulus formula: d_pc = 10^((m - M + 5)/5), we substitute m = 16 and M = -19 to get d_pc = 10^((16 - (-19) + 5)/5) = 10^(40/5) = 10^8 pc, which is equivalent to 100 Mpc.

If the Absolute Magnitude, M , of a Supernova Is