Solve the system. To do so, substitute $a + b i$ for $( 7 - 4 i ) - ( 3 + 2 i )$ and $4 - 6 i$ for $\frac { 1 } { y }$ and solve for $\alpha$ and $b$ . Then find $x$ and $y$ using the fact that $a = \frac { 1 } { x }$ and $b = \frac { 1 } { y }$ . $\left\{ \begin{array} { l }
\frac { 1 } { x } + \frac { 1 } { y } = \frac { 11 } { 30 } \
\frac { 1 } { x } - \frac { 1 } { y } = \frac { 1 } { 30 }
\end{array} \right.$

Question

Solve the system. To do so, substitute $a + b i$ for $( 7 - 4 i ) - ( 3 + 2 i )$ and $4 - 6 i$ for $\frac { 1 } { y }$ and solve for $\alpha$ and $b$ . Then find $x$ and $y$ using the fact that $a = \frac { 1 } { x }$ and $b = \frac { 1 } { y }$ . $\left\{ \begin{array} { l } 
\frac { 1 } { x } + \frac { 1 } { y } = \frac { 11 } { 30 } \
\frac { 1 } { x } - \frac { 1 } { y } = \frac { 1 } { 30 }
\end{array} \right.$

Quizplus · Accepted Answer

The Answer of Solve the system. To do so, substitute $a + b i$ for $( 7 - 4 i ) - ( 3 + 2 i )$ and $4 - 6 i$ for $\frac { 1 } { y }$ and solve for $\alpha$ and $b$ . Then find $x$ and $y$ using the fact that $a = \frac { 1 } { x }$ and $b = \frac { 1 } { y }$ . $\left\{ \begin{array} { l } 
\frac { 1 } { x } + \frac { 1 } { y } = \frac { 11 } { 30 } \
\frac { 1 } { x } - \frac { 1 } { y } = \frac { 1 } { 30 }
\end{array} \right.$

Solve the System a+bia + b ia+bi For (7−4i)−(3+2i)( 7 - 4 i ) - ( 3 + 2 i )(7−4i)−(3+2i)

Solve the System $a + b i$ For $( 7 - 4 i ) - ( 3 + 2 i )$