Solve the system. Give your answer as an ordered triple in the form of ( a, b, c ).
$\left\{ \begin{array} { l }
8 a - 3 b = 1 \
6 a - 10 c = 1 \
3 b - 12 c = 0
\end{array} \right.$
A) $\left( - \frac { 1 } { 4 } , 1 , - \frac { 1 } { 4 } \right)$
B) $\left( \frac { 1 } { 4 } , - 1 , \frac { 1 } { 4 } \right)$
C) $\left( - \frac { 1 } { 4 } , - 1 , - \frac { 1 } { 4 } \right)$
D) The system is inconsistent.
E) The equations are dependent.

Question

Solve the system. Give your answer as an ordered triple in the form of ( a, b, c ). 
$\left\{ \begin{array} { l } 
8 a - 3 b = 1 \
6 a - 10 c = 1 \
3 b - 12 c = 0
\end{array} \right.$
A) $\left( - \frac { 1 } { 4 } , 1 , - \frac { 1 } { 4 } \right)$
B) $\left( \frac { 1 } { 4 } , - 1 , \frac { 1 } { 4 } \right)$
C) $\left( - \frac { 1 } { 4 } , - 1 , - \frac { 1 } { 4 } \right)$
D) The system is inconsistent.
E) The equations are dependent.

Quizplus · Accepted Answer

The Answer of Solve the system. Give your answer as an ordered triple in the form of ( a, b, c ). 
$\left\{ \begin{array} { l } 
8 a - 3 b = 1 \
6 a - 10 c = 1 \
3 b - 12 c = 0
\end{array} \right.$
A) $\left( - \frac { 1 } { 4 } , 1 , - \frac { 1 } { 4 } \right)$
B) $\left( \frac { 1 } { 4 } , - 1 , \frac { 1 } { 4 } \right)$
C) $\left( - \frac { 1 } { 4 } , - 1 , - \frac { 1 } { 4 } \right)$
D) The system is inconsistent.
E) The equations are dependent.

Solve the System {8a−3b=16a−10c=13b−12c=0\left\{ \begin{array} { l } 8 a - 3 b = 1 \\6 a - 10 c = 1 \\3 b - 12 c = 0\end{array} \right.⎩⎨⎧​8a−3b=16a−10c=13b−12c=0​

Solve the System $\left\{ \begin{array} { l } 8 a - 3 b = 1 \\6 a - 10 c = 1 \\3 b - 12 c = 0\end{array} \right.$