Solve the inequality: $3 ( 3 x - 5 ) - 5 ( x - 4 ) \geq 4 x + 5$
A) no solution
B) $( - \infty , \infty )$
C) $( - \infty , 0 ]$
D) $[ 0 , \infty )$

Question

Quizplus · Accepted Answer

First, distribute the numbers outside the parentheses: $9x - 15 - 5x + 20 \geq 4x + 5$. Simplify to get $4x + 5 \geq 4x + 5$. This shows that for all values of $x$, the inequality holds true, indicating that the solution is all real numbers, or $( - \infty , \infty )$.

Solve the Inequality 3(3x−5)−5(x−4)≥4x+53 ( 3 x - 5 ) - 5 ( x - 4 ) \geq 4 x + 53(3x−5)−5(x−4)≥4x+5

Solve the Inequality $3 ( 3 x - 5 ) - 5 ( x - 4 ) \geq 4 x + 5$