Solve: $\frac { 1 } { f } = \frac { 1 } { s _ { 1 } } + \frac { 1 } { s _ { 2 } }$ for $f$
A) $f = \frac { s _ { 1 } s _ { 2 } } { s _ { 1 } + s _ { 2 } }$
B) $f = + 1$
C) $f = s _ { 1 } + s _ { 2 }$
D) $f = \frac { s _ { 1 } s _ { 2 } } { s _ { 1 } - s _ { 2 } }$

Question

Quizplus · Accepted Answer

To solve for $f$, we take the reciprocal of both sides of the equation, which gives us $f = \frac { s _ { 1 } s _ { 2 } } { s _ { 1 } + s _ { 2 } }$. This is because when you take the reciprocal of a sum of reciprocals, you multiply the denominators and divide by the sum of the denominators.

Solve 1f=1s1+1s2\frac { 1 } { f } = \frac { 1 } { s _ { 1 } } + \frac { 1 } { s _ { 2 } }f1​=s1​1​+s2​1​

Solve $\frac { 1 } { f } = \frac { 1 } { s _ { 1 } } + \frac { 1 } { s _ { 2 } }$