Square both sides of the equation. $\sqrt { x + 3 } + 2 = \sqrt { x - 1 }$
A) $x + 5 = x - 1$
B) $x + 7 = x - 1$
C) $x + 2 \sqrt { x + 3 } + 7 = x - 1$
D) $x + 4 \sqrt { x + 3 } + 7 = x - 1$

Question

Quizplus · Accepted Answer

When you square both sides of the equation $\sqrt { x + 3 } + 2 = \sqrt { x - 1 }$, you get $x + 4 \sqrt { x + 3 } + 7 = x - 1$.

Square Both Sides of the Equation x+3+2=x−1\sqrt { x + 3 } + 2 = \sqrt { x - 1 }x+3​+2=x−1​

Square Both Sides of the Equation $\sqrt { x + 3 } + 2 = \sqrt { x - 1 }$