$$E _ { L I N E } = \sqrt { E_ R ^ { 2 } + E_ X ^ { 2 } }$$ What voltage is required to force a 4.5-amp current through an electric iron having a resistance of 25.5 ohms?

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The Answer of $$E _ { L I N E } = \sqrt { E_ R ^ { 2 } + E_ X ^ { 2 } }$$ What voltage is required to force a 4.5-amp current through an electric iron having a resistance of 25.5 ohms?

ELINE=ER2+EX2E _ { L I N E } = \sqrt { E_ R ^ { 2 } + E_ X ^ { 2 } }ELINE​=ER2​+EX2​​

$E _ { L I N E } = \sqrt { E_ R ^ { 2 } + E_ X ^ { 2 } }$