Factor completely. $72 b x ^ { 2 } - 42 b x - 9 b$
A) $3 b ( 6 x + 1 ) ( 4 x - 3 )$
B) $b ( 6 x + 1 ) ( 4 x - 3 )$
C) $3 b ( 6 x - 1 ) ( 4 x - 6 )$
D) $3 b ( 6 x - 1 ) ( 4 x + 3 )$
E) $3 b ( 6 x - 1 ) ( 4 x - 3 )$

Name: Factor completely. $72 b x ^ { 2 } - 42 b x - 9 b$ A) $3 b ( 6 x + 1 ) ( 4 x - 3 )$ B) $b ( 6 x + 1 ) ( 4 x - 3 )$ C) $3 b ( 6 x - 1 ) ( 4 x - 6 )$ D) $3 b ( 6 x - 1 ) ( 4 x + 3 )$ E) $3 b ( 6 x - 1 ) ( 4 x - 3 )$
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The Answer is A

Factor Completely 72bx2−42bx−9b72 b x ^ { 2 } - 42 b x - 9 b72bx2−42bx−9b

Factor Completely $72 b x ^ { 2 } - 42 b x - 9 b$