Factor. $s ^ { 3 } + 7 s ^ { 2 } + 29 s$
A) $s \left( s ^ { 2 } + 7 s + 29 s \right)$
B) $s ^ { 2 } \left( s ^ { 2 } + 7 s + 29 \right)$
C) $s ^ { 3 } ( 1 + 7 s + 29 )$
D) $s \left( s ^ { 2 } + 7 s + 29 \right)$
E) $s \left( s ^ { 3 } + 7 s ^ { 2 } + 29 \right)$

Question

Quizplus · Accepted Answer

The given expression is a polynomial that can be factored by grouping. First, we can factor out an s from all three terms: $$s ^ { 3 } + 7 s ^ { 2 } + 29 s = s(s ^ { 2 } + 7 s + 29)$$ The quadratic expression inside the parentheses cannot be factored further using real numbers, so the final answer is D: $$s \left( s ^ { 2 } + 7 s + 29 \right)$$

Factor s3+7s2+29ss ^ { 3 } + 7 s ^ { 2 } + 29 ss3+7s2+29s

Factor $s ^ { 3 } + 7 s ^ { 2 } + 29 s$