Factor the trinomial completely. $m ^ { 2 } - 4 m - 21$
A) $( m - 7 ) ( m - 3 )$
B) $( m + 7 ) ( m - 3 )$
C) $( m - 7 ) ( m + 3 )$
D) $( m + 7 ) ( m + 3 )$
E) not factorable

Question

Quizplus · Accepted Answer

The correct factoring of $m^2 - 4m - 21$ is $(m - 7)(m + 3)$, because when multiplied out, the outer and inner products give -4m and the constant term is -21.

Factor the Trinomial Completely m2−4m−21m ^ { 2 } - 4 m - 21m2−4m−21

Factor the Trinomial Completely $m ^ { 2 } - 4 m - 21$