The measurement is $4 \frac { 4 } { 24 }$ in ³ . Find the precision and the greatest possible error of the measurement. A) $\frac { 1 } { 24 }$ in ³ , $\frac { 1 } { 24 }$ in ³ B) $\frac { 1 } { 48 }$ in ³ , $\frac { 1 } { 48 }$ in ³ C) $\frac { 1 } { 24 }$ in ³ , $\frac { 1 } { 48 }$ in ³ D) $\frac { 1 } { 48 }$ in ³ , $\frac { 1 } { 24 }$ in ³ E) none of these

Question

Quizplus · Accepted Answer

The precision is determined by the smallest unit given, which is $\frac{1}{24}$ in ³. To find the greatest possible error, we must look at the place value immediately to the right of the last digit given, which is in the hundredths place (S1). Therefore, the greatest possible error is half of the unit in that place value, which is $\frac{1}{48}$ in ³. So the precision is $\frac{1}{24}$ in ³ and the greatest possible error is $\frac{1}{48}$ in ³, leading to choice C.

The Measurement Is 44244 \frac { 4 } { 24 }4244​

The Measurement Is $4 \frac { 4 } { 24 }$