Solve each equation for D . Match each equation with the corresponding solution.
-$D = \frac { Q X } { Q + X }$
A) $\frac { D } { Q } = \frac { X } { Q + X }$
B) $\frac { 1 } { D } = \frac { 1 } { Q } - \frac { 1 } { X }$

Question

Solve each equation for D . Match each equation with the corresponding solution.
-$D = \frac { Q X } { Q + X }$ 
A) $\frac { D } { Q } = \frac { X } { Q + X }$ 
B) $\frac { 1 } { D } = \frac { 1 } { Q } - \frac { 1 } { X }$

Quizplus · Accepted Answer

To solve the given equation $D = \frac { Q X } { Q + X }$ for D in terms of Q and X, we can see that it already matches the form in option A directly without any manipulation. Option B, when simplified, does not match the given equation's form.

Solve Each Equation for D D=QXQ+XD = \frac { Q X } { Q + X }D=Q+XQX​

Solve Each Equation for D $D = \frac { Q X } { Q + X }$