Solve the quadratic equation. 4 t ² = 32 A) $n = \sqrt { 2 } \text { or } n = - \sqrt { 2 }$ B) n = 4 or n = $-$ 4 C) $n = 2 \sqrt { 2 } \text { or } n = - 2 \sqrt { 2 }$ D) n = 2 or n = $-$ 2

Question

Quizplus · Accepted Answer

First, simplify the equation:

$4t^2 - 32 = 0$
$t^2 - 8 = 0$
$t^2 = 8$
$t = \pm \sqrt{8}$
$t = \pm 2\sqrt{2}$

Therefore, the correct choices are (C), as they match the solutions found above.

Solve the Quadratic Equation n=2 or n=−2n = \sqrt { 2 } \text { or } n = - \sqrt { 2 }n=2​ or n=−2​

Solve the Quadratic Equation $n = \sqrt { 2 } \text { or } n = - \sqrt { 2 }$