Solve each quadratic equation by using the factoring method. Match each equation with the corresponding solution.
-$n = - 6 , n = \frac { 1 } { 2 }$
A) $2 n ^ { 2 } + 11 n - 6 = 0$
B) $2 n ^ { 2 } + 9 n - 5 = 0$
C) $2 n ^ { 2 } + 15 n - 8 = 0$

Question

Solve each quadratic equation by using the factoring method. Match each equation with the corresponding solution.
-$n = - 6 , n = \frac { 1 } { 2 }$ 
A) $2 n ^ { 2 } + 11 n - 6 = 0$ 
B) $2 n ^ { 2 } + 9 n - 5 = 0$ 
C) $2 n ^ { 2 } + 15 n - 8 = 0$

Quizplus · Accepted Answer

To solve the quadratic equation $2n^2 + 11n - 6 = 0$ by factoring, we look for two numbers that multiply to $2 \times -6 = -12$ and add to $11$. These numbers are $12$ and $-1$, so we can rewrite the equation as $2n^2 + 12n - n - 6 = 0$, which factors to $2n(n + 6) - 1(n + 6) = 0$, leading to $(2n - 1)(n + 6) = 0$. This gives us the solutions $n = \frac{1}{2}$ and $n = -6$.

Solve Each Quadratic Equation by Using the Factoring Method n=−6,n=12n = - 6 , n = \frac { 1 } { 2 }n=−6,n=21​

Solve Each Quadratic Equation by Using the Factoring Method $n = - 6 , n = \frac { 1 } { 2 }$