Solve the inequality. $x ( x + 3 ) ( x - 8 ) \leq 0$
A) $( - \infty , - 8 ] \cup [ 3 , \infty )$
B) $( - \infty , 3 ] \cup [ 8 , \infty )$
C) $( - \infty , - 3 ] \cup [ 0,8 ]$

Question

Quizplus · Accepted Answer

The roots of the inequality are x = 0, x = -3, and x = 8. To solve $x(x+3)(x-8) \leq 0$, we test intervals around these roots. The correct intervals where the expression is less than or equal to zero are $(- \infty, -3]$ and $[0, 8]$.

Solve the Inequality x(x+3)(x−8)≤0x ( x + 3 ) ( x - 8 ) \leq 0x(x+3)(x−8)≤0

Solve the Inequality $x ( x + 3 ) ( x - 8 ) \leq 0$