Solve the inequality. $9 x ^ { 2 } + 30 x + 25 \leq 0$
A) $x = - \frac { 5 } { 3 }$
B) $x = \frac { 3 } { 5 }$
C) $x = \frac { 5 } { 3 }$

Question

Quizplus · Accepted Answer

The given inequality can be rewritten as $(3x + 5)^2 \leq 0$. This implies that $3x + 5 = 0$, solving for $x$ gives $x = -\frac{5}{3}$. Since it's a perfect square, the only solution is when the expression inside the square is zero.

Solve the Inequality 9x2+30x+25≤09 x ^ { 2 } + 30 x + 25 \leq 09x2+30x+25≤0

Solve the Inequality $9 x ^ { 2 } + 30 x + 25 \leq 0$